SC.hasFirebug() bug?

Smart GWT Technical Q&A
1

SC.hasFirebug() is returning true when Firebug is disabled.
It seems to me that the SC.hasFirebug () method is named in a way that indicates whether Firebug is installed and not whether it is enabled.
On the other hand, the documentation says it returns true if Firebug is enabled.

I am using:
SmartGWT: 2.5
FireFox: 6.0.2
Firebug: 1.8.4

Original code:

    /**
     * Return true if Firebug is enabled.
     *
     * @return true if firebug is enabled
     */
    public static native boolean hasFirebug() /*-{
		 return $wnd.isc.Browser.isMoz && window.console != null && window.console.trace != null;
    }-*/;

So I tried using this to get the Firebug version, and if it is != null, then Firebug is running and enabled…

public static native String getFirebugVersion () /*-{
    if (
      typeof $wnd.console !== 'undefined' &&
      typeof $wnd.console.firebug !== 'undefined') {
      return "" + $wnd.console.firebug;
    }
    else {
      return null;
    }
  }-*/;

Notes:
So I am using this to get the firebug version.
The first ‘undefined’ check is needed because otherwise the “$wnd.console.firebug” check fails in IE.
I had to concat the firebug version to “” otherwise I would get a JS error that the returned object is not a String.

So I am looking for comments on this.
Is it right, is it wrong, or is there something else I am missing here?